MIL- STD-883F 2004 TEST METHOD STANDARD MICROCIRCUITS - 第354页
MIL-STD-883F METHOD 2019.7 07 March 2003 4 NOTE S: 1. All die area lar ger than 64 x 10 -4 (IN) 2 shall withst and a minimum f orce of 2. 5 kg or a mul tiple there of (see 3.2 ). 2. All die area l arger t han or equal to…
MIL-STD-883F
METHOD 2019.7
07 March 2003
3
FIGURE 2019-1. Compliant interface on contact tool distributes
load to the irregular edge of the die
.
FIGURE 2019-2. Rotate the die contact tool or the device
for parallel alignment
.
FIGURE 2019-3. The contact tool shall load against that edge
of the die which forms an angle ≈ 90° with
the header/substrate
.
MIL-STD-883F
METHOD 2019.7
07 March 2003
4
NOTES:
1. All die area larger than 64 x 10
-4
(IN)
2
shall withstand a minimum force of 2.5 kg or a multiple
thereof (see 3.2).
2. All die area larger than or equal to 5 x 10
-4
(IN)
2
but small than or equal to 64 x 10
-4
(IN)
2
shall withstand a
minimum force as determined from the chart of Figure 2019.4
3. All die area smaller than 5 x 10
-4
(IN)
2
shall withstand a minimum force (1.0X) of 0.04 kg/10
-4
(IN)
2
or a minimum force (2X) of 0.08 kg/10
-4
(IN)
2.
FIGURE 2019-4. Die shear strength criteria (minimum force versus die attach area)
.
DIE AREA (10
-
4
IN
2
)
MIL-STD-883F
METHOD 2019.7
07 March 2003
5
Examples of determining die strength requirements based on die area.
Example 1:
Die Area of device measuring .02 inches by .02 inches.
Die Size = .02 X .02 = .0004 IN
2
= 4 X 10
-4
(IN
2
).
Because die size is less than 5 X 10
-4
(IN
2
) use Note 3 which states the value of minimum force required is 0.04
kg/10
-4
(IN
2
) at (1X), 0.05 kg/10
-4
(IN
2
) at (1.25X), or 0.08 kg/10
-4
(IN
2
) at (2X). Thus the associated
minimum forces required are 0.16 kg, 0.20 kg and 0.32 kg, respectively.
Example 2:
Die Area of device measuring .04 inches by 0.04 inches.
Die Size = .04 X .04 = .0016 IN
2
= 16 X 10
-4
(IN
2
).
Because die size is between 5 X 10
-4
(IN
2
) and 64 X 10
-4
(IN
2
) use Note 2 which states the value of minimum
force required is to be determined based on the chart. The values for die size 16 X 10
-4
(IN
2
) are found
on the chart by reading 16 on the (10
-4
IN
2
) scale, then finding the coordinating force value on the (F)
scale. Doing so provides minimum forces required as .64 kg at (1X), .80 kg at (1.25X), and 1.28 kg at
(2X).
Example 3:
Die Area of device measuring .09 inches by .09 inches.
Die Size = .09 X .09 = .0081 IN
2
= 81 X 10
-4
(IN
2
).
Because die size is larger than 64 X 10
-4
(IN
2
) use Note 1 which states the value of minimum force required is 2.5
kg or a multiple thereof. Therefore, the minimum forces required are 2.5 kg at (1X), 3.125 kg at (1.25X),
and 5.0 kg at (2X).