00194932-20 User Manual CAN Test Box-Error Frame Diagnostic unit_en - 第98页
1 - 98 SIPLACE CAN Bus Edition 10/2018 98 4.10.3 CAN Bus SIPLACE D2 Fig. 4.10 - 5 CAN Bus structure D2
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Fig. 4.10 - 4 CAN Bus 1 in detail D1 machine
For the CAN Bus 2 (1MBit/s) you have to measure the terminator on the service-connector X12-
pa2. If the option WPC connected you should measure 40 ohm, if not the value is 60 ohm.
In the Fig. 4.10 - 4 for the component and tape cutter CAN Bus 2, there are four terminators in the
circuit, if the machine switch off and the component table connected. So you measure 30 ohm on
the connector (1).
When the machine is switch on, the Relays contacts K1 will be open and the normal termination
of 60 Ohm is available.
Now, If you change or disconnect a component table, the CAN Bus is working normal, because
the relay contact K1 will be closed and the other terminator is available.
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SIPLACE CAN Bus Edition 10/2018
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4.10.3 CAN Bus SIPLACE D2
Fig. 4.10 - 5 CAN Bus structure D2
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Fig. 4.10 - 6 CAN Bus structure D2 operation diagram 03043798-010302LD3
C A N T e r m i n a t i o n o n :
S 1 . 8 = O N
C A N T e r m i n a t i o n o n :
S 1 . 5 = O N
f i x e d C A N T e r m i n a t i o n o n
G a n t r y H e a d D i s t r i b u t
o r
0 3 0 3 8 0 0 2
f i x e d C A N T e r m i n a t i o n o n
G a n t r y H e a d D i s t r i b u t o r
0 3 0 3 8 0 0 2
C A N I / O m o d u l e
0 0 3 5 5 0 5 1 ( q b )
B E - T i s c h 2
C o m p o n e n t s t a b l e 2
0 3 0 4 1 3 1 5 )
M a s c h i n e n C o n t r o l l e r
M a c h i n e c o n t r o l l e r
0 3 0 3 2 3 4 2 ( p a )
C A N - B U S 1 D 2
A x i s U n i t A 3 6 4
0 3 0 4 2 0 4 7
T r a n s p o r t s t e u e r u n g T S P 2 0 1
C o n v e y o r c o n t r o l l e r T S P 2 0 1
0 3 0 4 3 8 3 2
C A N 2 C A N 1
X 2 2 a o
X 2 2 a o
X 3 0 _ 1 s q
X 3 0 _ 1 s q
X 1 1 p aX 1 2 p a
X 1 1 p a
X 1 b f
H a u p t v e r t e i l e r
M a i n D i s t r i b u t o r
0 3 0 5 0 1 7 8 ( b f )
U n t e r v e r t e i l e r
S u b D i s t r i b u t o r
0 3 0 5 0 1 7 7 ( a f )
S c h l e p p -
V e r t e i l e r
T r a i l i n g
d i s t r i b u t o r
0 3 0 3 8 6 9 0
X 4 0 b a
X 4 0 b a
X 1 b f X 1 a f
X 1 a f
X 3 0 _ 2 s q
X 3 0 _ 2 s q
0 3 0 5 0 1 6 3
X 1 1 p a 2 S e r v i c e
P o r t a l 2 / G a n t r y 2
S e k t o r 2
S e c t o r 2
S e k t o r 1
S e c t o r 1
C A N - B U S 2 S u b
0 3 0 5 0 1 6 5
X 1 q b
X 1 q e
C A N - I n t e r f a c e
0 3 0 3 2 3 4 6 ( q e )
X 4 b h
X 4 b h
X 3 q e
X 3 q e
X 5 q e
X 5 q e
X 4 q e
X 4 q e
G u r t s c h n e i d e r 2
T a p e c u t t e r 2
0 3 0 0 6 4 1 1 ( b h )
G u r t s c h n e i d e r 1
T a p e c u t t e r 1
0 3 0 0 6 4 1 1 ( a h )
X 1 r b
X 1 r b
X 2 r b
X 2 r b
B E - T i s c h 1
C o m p o n e n t s t a b l e 1
0 3 0 4 1 3 1 5
C A N - B U S t e r m i n a t o r
c o m p o n e n t t a b l e
0 3 0 4 6 8 6 3
X 4 a h
X 4 a h
X 1 q a
X 1 q a
X 2 q a
X 2 q a
C A N - B U S t e r m i n a t o r
c o m p o n e n t t a b l e
0 3 0 4 6 8 6 3
X 2 q b
X 2 q e
S c h l e p p -
V e r t e i l e r
T r a i l i n g
d i s t r i b u t o r
0 3 0 3 8 6 9 0
X 4 0 a a
X 4 0 a a
P o r t a l 1 / G a n t r y 1
X 1 2 p a 2 S e r v i c e
X 1 2 p a
C A N - B U S 2 D 2
0 3 0 5 0 6 6 6